Printing only even number using
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int num,even=0;
cout<<"Enter Number of limit: ";
cin>>num;
// loop execute at least one time doesn't matter condition true or false
do
{
cout<<even<<" "; // print even value
even = even+2; // increment value by 2
}
while(even<num); // check condition
getch();
}
OUTPUT
Enter Number of limit: 9
0 2 4 6 8
a simple menu demonstration of two number operation using switch and do – while loop
#include<iostream.h>
#include<conio.h>
void main()
{
int ch;
float num1,num2;
// creating menu wizard using do-while loop
do{
clrscr();
cout<<"Enter any two number: ";
cin>>num1>>num2;
cout<<"\nselection operation\n";
cout<<"1> Addition"<<endl;
cout<<"2> Substriction"<<endl;
cout<<"3> Multiply"<<endl;
cout<<"4> Division"<<endl;
cout<<"0> Exit"<<endl;
cout<<"Your choice:";
cin>>ch;
cout<<endl;
switch(ch)
{
case 1: cout<<"\nAddition are"<<endl;
cout<<num1<<"+"<<num2<<" = "<<num1+num2;
getch();
break;
case 2: cout<<"\nsubstriction are"<<endl;
cout<<num1<<"-"<<num2<<" = "<<num1-num2;
getch();
break;
case 3: cout<<"\nmultiply are"<<endl;
cout<<num1<<"x"<<num2<<" = "<<num1*num2;
getch();
break;
case 4: cout<<"\ndivision are"<<endl;
cout<<num1<<"/"<<num2<<" = "<<num1/num2;
getch();
break;
}
}while(ch!=0);
}
OUTPUT:-
Enter any two number: 12 13
selection operation
1> Addition
2> Substriction
3> Multiply
4> Division
0> Exit
Your choice:
multiply are
12x13 = 156
selection operation
1> Addition
2> Substriction
3> Multiply
4> Division
0> Exit
Your choice:0
Related exercise,